olymmath

EGMO 2015 Problem 6

  • Day 2

Let HH be the orthocenter and GG be the centroid of acute-angled triangle △ABC\triangle A B C with AB≠ACA B \neq A C. The line AGA G intersects the circumcircle of △ABC\triangle A B C at AA and PP. Let P′P^{\prime} be the reflection of PP in the line BCB C. Prove that ∠CAB=60∘\angle C A B=60^{\circ} if and only if HG=GP′H G=G P^{\prime}. (Ukraine)

Dataset text NuminaMath olympiads. Quoted with source.

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