olymmath

CMO 2022 Problem 5

  • Paper

Let ABCDEA B C D E be a convex pentagon such that the five vertices lie on a circle and the five sides are tangent to another circle inside the pentagon. There are (53)=10\binom{5}{3}=10 triangles which can be formed by choosing 3 of the 5 vertices. For each of these 10 triangles, mark its incenter. Prove that these 10 incenters lie on two concentric circles.

Dataset text NuminaMath olympiads. Quoted with source.

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