olymmath

BALTIC-WAY 2023 Problem 13

    Let ABCA B C be an acute triangle with AB<ACA B<A C and incentre II. Let DD be the projection of II onto BCB C. Let HH be the orthocentre of ABCA B C. Given ∠IDH=∠CBA−∠ACB\angle I D H=\angle C B A-\angle A C B, prove that AH=2⋅IDA H=2 \cdot I D.

    Dataset text NuminaMath olympiads. Quoted with source.

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