olymmath

BALTIC-WAY 2010 Problem 15

  • Answer

The points MM and NN are chosen on the angle bisector ALA L of a triangle ABCA B C such that ∠ABM=∠ACN=23∘.X\angle A B M=\angle A C N=23^{\circ} . X is a point inside the triangle such that BX=CXB X=C X and ∠BXC=2∠BML\angle B X C=2 \angle B M L. Find ∠MXN\angle M X N.

Dataset text NuminaMath olympiads. Quoted with source.

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46^{\circ}

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