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BALTIC-WAY 2006 Problem 12

  • Answer

Let ABCA B C be a triangle, let B1B_{1} be the midpoint of the side ABA B and C1C_{1} the midpoint of the side ACA C. Let PP be the point of intersection, other than AA, of the circumscribed circles around the triangles ABC1A B C_{1} and AB1CA B_{1} C. Let P1P_{1} be the point of intersection, other than AA, of the line APA P with the circumscribed circle around the triangle AB1C1A B_{1} C_{1}. Prove that 2AP=3AP12 A P=3 A P_{1}.

Dataset text NuminaMath olympiads. Quoted with source.

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2 AP = 3 AP_1

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