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BALTIC-WAY 2005 Problem 3

  • Answer

Consider the sequence aka_{k} defined by a1=1,a2=12a_{1}=1, a_{2}=\frac{1}{2},

ak+2=ak+12ak+1+14akak+1 for k≥1a_{k+2}=a_{k}+\frac{1}{2} a_{k+1}+\frac{1}{4 a_{k} a_{k+1}} \text { for } k \geq 1

Prove that

1a1a3+1a2a4+1a3a5+⋯+1a98a100<4\frac{1}{a_{1} a_{3}}+\frac{1}{a_{2} a_{4}}+\frac{1}{a_{3} a_{5}}+\cdots+\frac{1}{a_{98} a_{100}}<4

Dataset text NuminaMath olympiads. Quoted with source.

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