olymmath

BALTIC-WAY 2004 Problem 19

    DD is the midpoint of the side BCB C of the given triangle ABC.MA B C . M is a point on the side BCB C such that ∠BAM=∠DAC\angle B A M=\angle D A C. LL is the second intersection point of the circumcircle of the triangle CAMC A M with the side AB.KA B . K is the second intersection point of the circumcircle of the triangle BAMB A M with the side ACA C. Prove that KL∥BCK L \| B C.

    Dataset text NuminaMath olympiads. Quoted with source.

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