olymmath

BALTIC-WAY 2003 Problem 12

    Let ABCDA B C D be a square. Let MM be an inner point on side BCB C and NN be an inner point on side CDC D with ∠MAN=45∘\angle M A N=45^{\circ}. Prove that the circumcentre of AMNA M N lies on ACA C.

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator baltic-way/2003/p12 · Tag GE5CRY8RY7 · Edit this page on GitHub · Keys: j next, k previous