olymmath

BALTIC-WAY 2001 Problem 10

  • Answer

In a triangle ABCA B C, the bisector of ∠BAC\angle B A C meets the side BCB C at the point DD. Knowing that ∣BD∣⋅∣CD∣=∣AD∣2|B D| \cdot|C D|=|A D|^{2} and ∠ADB=45∘\angle A D B=45^{\circ}, determine the angles of triangle ABCA B C.

Dataset text NuminaMath olympiads. Quoted with source.

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\angle B A C=60^{\circ}, \angle A B C=105^{\circ}, \angle A C B=15^{\circ}

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