olymmath

BALTIC-WAY 1999 Problem 18

    Let mm be a positive integer such that m≡2( mod 4)m \equiv 2(\bmod 4). Show that there exists at most one factorization m=abm=a b where aa and bb are positive integers satisfying 0<a−b<5+44m+10<a-b<\sqrt{5+4 \sqrt{4 m+1}}.

    Dataset text NuminaMath olympiads. Quoted with source.

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