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BALKAN-SL 2021 N5

  • Answer

A natural number nn is given. Determine all (n−1)(n-1)-tuples of nonnegative integers a1,a2,…,an−1a_{1}, a_{2}, \ldots, a_{n-1} such that

[m2n−1]+[2m+a12n−1]+[22m+a22n−1]+[23m+a32n−1]+⋯+[2n−1m+an−12n−1]=m\left[\frac{m}{2^{n}-1}\right]+\left[\frac{2 m+a_{1}}{2^{n}-1}\right]+\left[\frac{2^{2} m+a_{2}}{2^{n}-1}\right]+\left[\frac{2^{3} m+a_{3}}{2^{n}-1}\right]+\cdots+\left[\frac{2^{n-1} m+a_{n-1}}{2^{n}-1}\right]=m

holds for all m∈Zm \in \mathbb{Z}. Proposed by Serbia

Dataset text NuminaMath olympiads. Quoted with source.

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a_{k}=2^{n-1}+2^{k-1}-1

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