olymmath

APMO 2015 Problem 1

  • Paper

Let ABCA B C be a triangle, and let DD be a point on side BCB C. A line through DD intersects side ABA B at XX and ray ACA C at YY. The circumcircle of triangle BXDB X D intersects the circumcircle ω\omega of triangle ABCA B C again at point Z≠BZ \neq B. The lines ZDZ D and ZYZ Y intersect ω\omega again at VV and WW, respectively. Prove that AB=VWA B=V W.

Dataset text NuminaMath olympiads. Quoted with source.

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