olymmath

APMO 1990

Asian Pacific Mathematics Olympiad 1990.

Paper

Problem 1

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In △ABC\triangle A B C, let D,E,FD, E, F be the midpoints of BC,AC,ABB C, A C, A B respectively and let GG be the centroid of the triangle. For each value of ∠BAC\angle B A C, how many non-similar triangles are there in which AEGFA E G F is a cyclic quadrilateral?

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Problem 2

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Let a1,a2,…,ana_{1}, a_{2}, \ldots, a_{n} be positive real numbers, and let SkS_{k} be the sum of products of a1,a2,…,ana_{1}, a_{2}, \ldots, a_{n} taken kk at a time. Show that

SkSn−k≥(nk)2a1a2…an, for k=1,2,…,n−1S_{k} S_{n-k} \geq\binom{ n}{k}^{2} a_{1} a_{2} \ldots a_{n}, \text { for } k=1,2, \ldots, n-1

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Problem 3

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Consider all the triangles ABCA B C which have a fixed base ABA B and whose altitude from CC is a constant hh. For which of these triangles is the product of its altitudes a maximum?

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Problem 4

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  • Answer

A set of 1990 persons is divided into non-intersecting subsets in such a way that (a) no one in a subset knows all the others in the subset; (b) among any three persons in a subset, there are always at least two who do not know each other; and (c) for any two persons in a subset who do not know each other, there is exactly one person in the same subset knowing both of them. (i) Prove that within each subset, every person has the same number of acquaintances. (ii) Determine the maximum possible number of subsets.

Note: it is understood that if a person AA knows person BB, then person BB will know person AA; an acquaintance is someone who is known. Every person is assumed to know one's self.

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Problem 5

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Show that for every integer n≥6n \geq 6, there exists a convex hexagon which can be dissected into exactly nn congruent triangles.

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