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AIME 2024a Problem 10

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Let △ABC\triangle ABC have side lengths AB=5AB=5, BC=9BC=9, CA=10CA=10. The tangents to circumcircle of △ABC\triangle ABC at BB and CC intersect at point DD, and AD‾\overline{AD} intersects the circumcircle at P≠AP \neq A. The length of APAP is equal to mn\frac{m}{n}, where mm and nn are relatively prime integers. Find m+nm + n.

Dataset text AIME 1983 to 2026. Quoted with source.

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