olymmath

AIME 2019a Problem 10

  • Paper
  • Answer

For distinct complex numbers z1,z2,…,z673z_1,z_2,\dots,z_{673}, the polynomial (x−z1)3(x−z2)3⋯(x−z673)3(x-z_1)^3(x-z_2)^3 \cdots (x-z_{673})^3can be expressed as x2019+20x2018+19x2017+g(x)x^{2019} + 20x^{2018} + 19x^{2017}+g(x), where g(x)g(x) is a polynomial with complex coefficients and with degree at most 20162016. The sum ∣∑1≤j<k≤673zjzk∣\left| \sum_{1 \le j <k \le 673} z_jz_k \right| can be expressed in the form mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm+n.

Dataset text AIME 1983 to 2026. Quoted with source.

Show the answer

352

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator aime/2019a/p10 · Tag A9KHVBXY64 · Edit this page on GitHub · Keys: j next, k previous