olymmath

AIME 2016a Problem 6

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In △ABC\triangle ABC let II be the center of the inscribed circle, and let the bisector of ∠ACB\angle ACB intersect ABAB at LL. The line through CC and LL intersects the circumscribed circle of △ABC\triangle ABC at the two points CC and DD. If LI=2LI=2 and LD=3LD=3, then IC=pqIC=\tfrac{p}{q}, where pp and qq are relatively prime positive integers. Find p+qp+q.

Dataset text AIME 1983 to 2026. Quoted with source.

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