olymmath

AIME 2011b

American Invitational Mathematics Examination 2011.

Paper

Problem 1

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Gary purchased a large beverage, but only drank mn\frac{m}n of it, where mm and nn are relatively prime positive integers. If he had purchased half as much and drunk twice as much, he would have wasted only 29\frac{2}{9} as much beverage. Find m+nm+n.

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Problem 2

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On square ABCDABCD, point EE lies on side ADAD and point FF lies on side BCBC, so that BE=EF=FD=30BE=EF=FD=30. Find the area of the square ABCDABCD.

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Problem 3

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The degree measures of the angles in a convex 18-sided polygon form an increasing arithmetic sequence with integer values. Find the degree measure of the smallest angle.

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Problem 4

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In triangle ABCABC, AB=20AB=20 and AC=11AC=11. The angle bisector of ∠A\angle A intersects BCBC at point DD, and point MM is the midpoint of ADAD. Let PP be the point of the intersection of ACAC and BMBM. The ratio of CPCP to PAPA can be expressed in the form mn\dfrac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm+n.

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Problem 5

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The sum of the first 20112011 terms of a geometric sequence is 200200. The sum of the first 40224022 terms is 380380. Find the sum of the first 60336033 terms.

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Problem 6

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Define an ordered quadruple of integers (a,b,c,d)(a, b, c, d) as interesting if 1≤a<b<c<d≤101 \le a<b<c<d \le 10, and a+d>b+ca+d>b+c. How many interesting ordered quadruples are there?

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Problem 7

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Ed has five identical green marbles, and a large supply of identical red marbles. He arranges the green marbles and some of the red ones in a row and finds that the number of marbles whose right hand neighbor is the same color as themselves is equal to the number of marbles whose right hand neighbor is the other color. An example of such an arrangement is GGRRRGGRG. Let mm be the maximum number of red marbles for which such an arrangement is possible, and let NN be the number of ways he can arrange the m+5m+5 marbles to satisfy the requirement. Find the remainder when NN is divided by 10001000.

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Problem 8

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Let z1,z2,z3,…,z12z_1,z_2,z_3,\dots,z_{12} be the 12 zeroes of the polynomial z12−236z^{12}-2^{36}. For each jj, let wjw_j be one of zjz_j or izji z_j. Then the maximum possible value of the real part of ∑j=112wj\sum_{j=1}^{12} w_j can be written as m+nm+\sqrt{n} where mm and nn are positive integers. Find m+nm+n.

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Problem 9

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Let x1,x2,...,x6x_1, x_2, ... , x_6 be non-negative real numbers such that x1+x2+x3+x4+x5+x6=1x_1 +x_2 +x_3 +x_4 +x_5 +x_6 =1, and x1x3x5+x2x4x6≥1540x_1 x_3 x_5 +x_2 x_4 x_6 \ge {\frac{1}{540}}. Let pp and qq be positive relatively prime integers such that pq\frac{p}{q} is the maximum possible value of x1x2x3+x2x3x4+x3x4x5+x4x5x6+x5x6x1+x6x1x2x_1 x_2 x_3 + x_2 x_3 x_4 +x_3 x_4 x_5 +x_4 x_5 x_6 +x_5 x_6 x_1 +x_6 x_1 x_2. Find p+qp+q.

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Problem 10

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A circle with center OO has radius 25. Chord AB‾\overline{AB} of length 30 and chord CD‾\overline{CD} of length 14 intersect at point PP. The distance between the midpoints of the two chords is 12. The quantity OP2OP^2 can be represented as mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find the remainder when m+nm + n is divided by 1000.

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Problem 11

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Let MnM_n be the n×nn \times n matrix with entries as follows: for 1≤i≤n1 \le i \le n, mi,i=10m_{i,i} = 10; for 1≤i≤n−11 \le i \le n - 1, mi+1,i=mi,i+1=3m_{i+1,i} = m_{i,i+1} = 3; all other entries in MnM_n are zero. Let DnD_n be the determinant of matrix MnM_n. Then ∑n=1∞18Dn+1\sum_{n=1}^{\infty} \frac{1}{8D_n+1} can be represented as pq\frac{p}{q}, where pp and qq are relatively prime positive integers. Find p+qp + q. Note: The determinant of the 1×11 \times 1 matrix [a][a] is aa, and the determinant of the 2×22 \times 2 matrix [abcd]=ad−bc\left[ {\begin{array}{cc} a & b \\ c & d \\ \end{array} } \right] = ad - bc; for n≥2n \ge 2, the determinant of an n×nn \times n matrix with first row or first column a1a_1 a2a_2 a3a_3 …\dots ana_n is equal to a1C1−a2C2+a3C3−⋯+(−1)n+1anCna_1C_1 - a_2C_2 + a_3C_3 - \dots + (-1)^{n+1}a_nC_n, where CiC_i is the determinant of the (n−1)×(n−1)(n - 1) \times (n - 1) matrix formed by eliminating the row and column containing aia_i.

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Problem 12

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Nine delegates, three each from three different countries, randomly select chairs at a round table that seats nine people. Let the probability that each delegate sits next to at least one delegate from another country be mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm + n.

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Problem 13

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Point PP lies on the diagonal ACAC of square ABCDABCD with AP>CPAP > CP. Let O1O_{1} and O2O_{2} be the circumcenters of triangles ABPABP and CDPCDP respectively. Given that AB=12AB = 12 and ∠O1PO2=120∘\angle O_{1}PO_{2} = 120^{\circ}, then AP=a+bAP = \sqrt{a} + \sqrt{b}, where aa and bb are positive integers. Find a+ba + b.

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Problem 14

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There are NN permutations (a1,a2,...,a30)(a_{1}, a_{2}, ... , a_{30}) of 1,2,…,301, 2, \ldots, 30 such that for m∈{2,3,5}m \in \left\{{2, 3, 5}\right\}, mm divides an+m−ana_{n+m} - a_{n} for all integers nn with 1≤n<n+m≤301 \leq n < n+m \leq 30. Find the remainder when NN is divided by 10001000.

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Problem 15

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Let P(x)=x2−3x−9P(x) = x^2 - 3x - 9. A real number xx is chosen at random from the interval 5≤x≤155 \le x \le 15. The probability that ⌊P(x)⌋=P(⌊x⌋)\left\lfloor\sqrt{P(x)}\right\rfloor = \sqrt{P(\left\lfloor x \right\rfloor)} is equal to a+b+c−de\frac{\sqrt{a} + \sqrt{b} + \sqrt{c} - d}{e} , where aa, bb, cc, dd, and ee are positive integers. Find a+b+c+d+ea + b + c + d + e.

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