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AIME 2011a Problem 6

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Suppose that a parabola has vertex (14,−98)\left(\frac{1}{4},-\frac{9}{8}\right) and equation y=ax2+bx+cy = ax^2 + bx + c, where a>0a > 0 and a+b+ca + b + c is an integer. The minimum possible value of aa can be written in the form pq\frac{p}{q}, where pp and qq are relatively prime positive integers. Find p+qp + q.

Dataset text AIME 1983 to 2026. Quoted with source.

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