olymmath

AIME 2008b Problem 8

  • Paper
  • Answer

Let a=π/2008a = \pi/2008. Find the smallest positive integer nn such that 2[cos⁡(a)sin⁡(a)+cos⁡(4a)sin⁡(2a)+cos⁡(9a)sin⁡(3a)+⋯+cos⁡(n2a)sin⁡(na)]2[\cos(a)\sin(a) + \cos(4a)\sin(2a) + \cos(9a)\sin(3a) + \cdots + \cos(n^2a)\sin(na)] is an integer.

Dataset text AIME 1983 to 2026. Quoted with source.

Show the answer

251

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator aime/2008b/p8 · Tag QZDXKYTNVN · Edit this page on GitHub · Keys: j next, k previous