olymmath

AIME 2008b Problem 1

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Let N=1002+992−982−972+962+⋯+42+32−22−12N = 100^2 + 99^2 - 98^2 - 97^2 + 96^2 + \cdots + 4^2 + 3^2 - 2^2 - 1^2, where the additions and subtractions alternate in pairs. Find the remainder when NN is divided by 10001000.

Dataset text AIME 1983 to 2026. Quoted with source.

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