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AIME 2005b Problem 14

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In triangle ABC,AB=13,BC=15,ABC, AB=13, BC=15, and CA=14.CA = 14. Point DD is on BC‾\overline{BC} with CD=6.CD=6. Point EE is on BC‾\overline{BC} such that ∠BAE≅∠CAD.\angle BAE\cong \angle CAD. Given that BE=pqBE=\frac pq where pp and qq are relatively prime positive integers, find q.q.

Dataset text AIME 1983 to 2026. Quoted with source.

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