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AIME 2004b Problem 9

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A sequence of positive integers with a1=1a_1=1 and a9+a10=646a_9+a_{10}=646 is formed so that the first three terms are in geometric progression, the second, third, and fourth terms are in arithmetic progression, and, in general, for all n≥1,n\ge1, the terms a2n−1,a2n,a2n+1a_{2n-1}, a_{2n}, a_{2n+1} are in geometric progression, and the terms a2n,a2n+1,a_{2n}, a_{2n+1}, and a2n+2a_{2n+2} are in arithmetic progression. Let ana_n be the greatest term in this sequence that is less than 10001000. Find n+an.n+a_n.

Dataset text AIME 1983 to 2026. Quoted with source.

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