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AIME 2003b Problem 11

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Triangle ABCABC is a right triangle with AC=7,AC = 7, BC=24,BC = 24, and right angle at C.C. Point MM is the midpoint of AB,AB, and DD is on the same side of line ABAB as CC so that AD=BD=15.AD = BD = 15. Given that the area of triangle CDMCDM may be expressed as mnp,\frac {m\sqrt {n}}{p}, where m,m, n,n, and pp are positive integers, mm and pp are relatively prime, and nn is not divisible by the square of any prime, find m+n+p.m + n + p.

Dataset text AIME 1983 to 2026. Quoted with source.

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