olymmath

AIME 2001a Problem 4

  • Paper
  • Answer

In triangle ABCABC, angles AA and BB measure 6060 degrees and 4545 degrees, respectively. The bisector of angle AA intersects BC‾\overline{BC} at TT, and AT=24AT=24. The area of triangle ABCABC can be written in the form a+bca+b\sqrt{c}, where aa, bb, and cc are positive integers, and cc is not divisible by the square of any prime. Find a+b+ca+b+c.

Dataset text AIME 1983 to 2026. Quoted with source.

Show the answer

291

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator aime/2001a/p4 · Tag 6R5D5Z5H3V · Edit this page on GitHub · Keys: j next, k previous