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AIME 1996 Problem 13

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In triangle ABCABC, AB=30AB=\sqrt{30}, AC=6AC=\sqrt{6}, and BC=15BC=\sqrt{15}. There is a point DD for which AD‾\overline{AD} bisects BC‾\overline{BC}, and ∠ADB\angle ADB is a right angle. The ratio [ADB][ABC]\frac{[ADB]}{[ABC]} can be written in the form mn\dfrac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm+n.

Dataset text AIME 1983 to 2026. Quoted with source.

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