olymmath

AIME 1995 Problem 9

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Triangle ABCABC is isosceles, with AB=ACAB=AC and altitude AM=11.AM=11. Suppose that there is a point DD on AM‾\overline{AM} with AD=10AD=10 and ∠BDC=3∠BAC.\angle BDC=3\angle BAC. Then the perimeter of △ABC\triangle ABC may be written in the form a+b,a+\sqrt{b}, where aa and bb are integers. Find a+b.a+b. [asy] import graph; size(5cm); real lsf=0.5; pen dps=linewidth(0.7)+fontsize(10); defaultpen(dps); pen ds=black; real xmin=-1.55,xmax=7.95,ymin=-4.41,ymax=5.3; draw((1,3)--(0,0)); draw((0,0)--(2,0)); draw((2,0)--(1,3)); draw((1,3)--(1,0)); draw((1,0.7)--(0,0)); draw((1,0.7)--(2,0)); label("1111",(1,1.63),W); dot((1,3),ds); label("AA",(1,3),N); dot((0,0),ds); label("BB",(0,0),SW); dot((2,0),ds); label("CC",(2,0),SE); dot((1,0),ds); label("MM",(1,0),S); dot((1,0.7),ds); label("DD",(1,0.7),NE); clip((xmin,ymin)--(xmin,ymax)--(xmax,ymax)--(xmax,ymin)--cycle);[/asy]

Dataset text AIME 1983 to 2026. Quoted with source.

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