olymmath

AIME 1994 Problem 1

  • Paper
  • Answer

The increasing sequence 3,15,24,48,… 3, 15, 24, 48, \ldots\, consists of those positive multiples of 3 that are one less than a perfect square. What is the remainder when the 1994th term of the sequence is divided by 1000?

Dataset text AIME 1983 to 2026. Quoted with source.

Show the answer

63

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator aime/1994/p1 · Tag BZ91P9PKY5 · Edit this page on GitHub · Keys: j next, k previous