olymmath

AIME 1990 Problem 11

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Someone observed that 6!=8⋅9⋅106! = 8 \cdot 9 \cdot 10. Find the largest positive integer nn^{}_{} for which n!n^{}_{}! can be expressed as the product of n−3n - 3_{}^{} consecutive positive integers.

Dataset text AIME 1983 to 2026. Quoted with source.

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Locator aime/1990/p11 · Tag 6A1WTV1SE5 · Edit this page on GitHub · Keys: j next, k previous